3.675 \(\int \frac {x^{4/3}}{a+b x} \, dx\)

Optimal. Leaf size=123 \[ \frac {3 a^{4/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{2 b^{7/3}}-\frac {a^{4/3} \log (a+b x)}{2 b^{7/3}}-\frac {\sqrt {3} a^{4/3} \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt {3} \sqrt [3]{a}}\right )}{b^{7/3}}-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b} \]

[Out]

-3*a*x^(1/3)/b^2+3/4*x^(4/3)/b+3/2*a^(4/3)*ln(a^(1/3)+b^(1/3)*x^(1/3))/b^(7/3)-1/2*a^(4/3)*ln(b*x+a)/b^(7/3)-a
^(4/3)*arctan(1/3*(a^(1/3)-2*b^(1/3)*x^(1/3))/a^(1/3)*3^(1/2))*3^(1/2)/b^(7/3)

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Rubi [A]  time = 0.06, antiderivative size = 123, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {50, 58, 617, 204, 31} \[ \frac {3 a^{4/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{2 b^{7/3}}-\frac {a^{4/3} \log (a+b x)}{2 b^{7/3}}-\frac {\sqrt {3} a^{4/3} \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt {3} \sqrt [3]{a}}\right )}{b^{7/3}}-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b} \]

Antiderivative was successfully verified.

[In]

Int[x^(4/3)/(a + b*x),x]

[Out]

(-3*a*x^(1/3))/b^2 + (3*x^(4/3))/(4*b) - (Sqrt[3]*a^(4/3)*ArcTan[(a^(1/3) - 2*b^(1/3)*x^(1/3))/(Sqrt[3]*a^(1/3
))])/b^(7/3) + (3*a^(4/3)*Log[a^(1/3) + b^(1/3)*x^(1/3)])/(2*b^(7/3)) - (a^(4/3)*Log[a + b*x])/(2*b^(7/3))

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 58

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(2/3)), x_Symbol] :> With[{q = Rt[-((b*c - a*d)/b), 3]}, -Sim
p[Log[RemoveContent[a + b*x, x]]/(2*b*q^2), x] + (Dist[3/(2*b*q), Subst[Int[1/(q^2 - q*x + x^2), x], x, (c + d
*x)^(1/3)], x] + Dist[3/(2*b*q^2), Subst[Int[1/(q + x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x
] && NegQ[(b*c - a*d)/b]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {x^{4/3}}{a+b x} \, dx &=\frac {3 x^{4/3}}{4 b}-\frac {a \int \frac {\sqrt [3]{x}}{a+b x} \, dx}{b}\\ &=-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b}+\frac {a^2 \int \frac {1}{x^{2/3} (a+b x)} \, dx}{b^2}\\ &=-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b}-\frac {a^{4/3} \log (a+b x)}{2 b^{7/3}}+\frac {\left (3 a^{5/3}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {a^{2/3}}{b^{2/3}}-\frac {\sqrt [3]{a} x}{\sqrt [3]{b}}+x^2} \, dx,x,\sqrt [3]{x}\right )}{2 b^{8/3}}+\frac {\left (3 a^{4/3}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt [3]{a}}{\sqrt [3]{b}}+x} \, dx,x,\sqrt [3]{x}\right )}{2 b^{7/3}}\\ &=-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b}+\frac {3 a^{4/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{2 b^{7/3}}-\frac {a^{4/3} \log (a+b x)}{2 b^{7/3}}+\frac {\left (3 a^{4/3}\right ) \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}\right )}{b^{7/3}}\\ &=-\frac {3 a \sqrt [3]{x}}{b^2}+\frac {3 x^{4/3}}{4 b}-\frac {\sqrt {3} a^{4/3} \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{b^{7/3}}+\frac {3 a^{4/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )}{2 b^{7/3}}-\frac {a^{4/3} \log (a+b x)}{2 b^{7/3}}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 140, normalized size = 1.14 \[ \frac {-2 a^{4/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} \sqrt [3]{x}+b^{2/3} x^{2/3}\right )+4 a^{4/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} \sqrt [3]{x}\right )-4 \sqrt {3} a^{4/3} \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} \sqrt [3]{x}}{\sqrt [3]{a}}}{\sqrt {3}}\right )-12 a \sqrt [3]{b} \sqrt [3]{x}+3 b^{4/3} x^{4/3}}{4 b^{7/3}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(4/3)/(a + b*x),x]

[Out]

(-12*a*b^(1/3)*x^(1/3) + 3*b^(4/3)*x^(4/3) - 4*Sqrt[3]*a^(4/3)*ArcTan[(1 - (2*b^(1/3)*x^(1/3))/a^(1/3))/Sqrt[3
]] + 4*a^(4/3)*Log[a^(1/3) + b^(1/3)*x^(1/3)] - 2*a^(4/3)*Log[a^(2/3) - a^(1/3)*b^(1/3)*x^(1/3) + b^(2/3)*x^(2
/3)])/(4*b^(7/3))

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fricas [A]  time = 0.46, size = 116, normalized size = 0.94 \[ \frac {4 \, \sqrt {3} a \left (\frac {a}{b}\right )^{\frac {1}{3}} \arctan \left (\frac {2 \, \sqrt {3} b x^{\frac {1}{3}} \left (\frac {a}{b}\right )^{\frac {2}{3}} - \sqrt {3} a}{3 \, a}\right ) - 2 \, a \left (\frac {a}{b}\right )^{\frac {1}{3}} \log \left (x^{\frac {2}{3}} - x^{\frac {1}{3}} \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right ) + 4 \, a \left (\frac {a}{b}\right )^{\frac {1}{3}} \log \left (x^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right ) + 3 \, {\left (b x - 4 \, a\right )} x^{\frac {1}{3}}}{4 \, b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)/(b*x+a),x, algorithm="fricas")

[Out]

1/4*(4*sqrt(3)*a*(a/b)^(1/3)*arctan(1/3*(2*sqrt(3)*b*x^(1/3)*(a/b)^(2/3) - sqrt(3)*a)/a) - 2*a*(a/b)^(1/3)*log
(x^(2/3) - x^(1/3)*(a/b)^(1/3) + (a/b)^(2/3)) + 4*a*(a/b)^(1/3)*log(x^(1/3) + (a/b)^(1/3)) + 3*(b*x - 4*a)*x^(
1/3))/b^2

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giac [A]  time = 1.21, size = 136, normalized size = 1.11 \[ -\frac {a \left (-\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x^{\frac {1}{3}} - \left (-\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{b^{2}} + \frac {\sqrt {3} \left (-a b^{2}\right )^{\frac {1}{3}} a \arctan \left (\frac {\sqrt {3} {\left (2 \, x^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{b^{3}} + \frac {\left (-a b^{2}\right )^{\frac {1}{3}} a \log \left (x^{\frac {2}{3}} + x^{\frac {1}{3}} \left (-\frac {a}{b}\right )^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )}{2 \, b^{3}} + \frac {3 \, {\left (b^{3} x^{\frac {4}{3}} - 4 \, a b^{2} x^{\frac {1}{3}}\right )}}{4 \, b^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)/(b*x+a),x, algorithm="giac")

[Out]

-a*(-a/b)^(1/3)*log(abs(x^(1/3) - (-a/b)^(1/3)))/b^2 + sqrt(3)*(-a*b^2)^(1/3)*a*arctan(1/3*sqrt(3)*(2*x^(1/3)
+ (-a/b)^(1/3))/(-a/b)^(1/3))/b^3 + 1/2*(-a*b^2)^(1/3)*a*log(x^(2/3) + x^(1/3)*(-a/b)^(1/3) + (-a/b)^(2/3))/b^
3 + 3/4*(b^3*x^(4/3) - 4*a*b^2*x^(1/3))/b^4

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maple [A]  time = 0.01, size = 121, normalized size = 0.98 \[ \frac {3 x^{\frac {4}{3}}}{4 b}+\frac {\sqrt {3}\, a^{2} \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x^{\frac {1}{3}}}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{\left (\frac {a}{b}\right )^{\frac {2}{3}} b^{3}}+\frac {a^{2} \ln \left (x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{\left (\frac {a}{b}\right )^{\frac {2}{3}} b^{3}}-\frac {a^{2} \ln \left (x^{\frac {2}{3}}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x^{\frac {1}{3}}+\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{2 \left (\frac {a}{b}\right )^{\frac {2}{3}} b^{3}}-\frac {3 a \,x^{\frac {1}{3}}}{b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(4/3)/(b*x+a),x)

[Out]

3/4*x^(4/3)/b-3*a*x^(1/3)/b^2+a^2/b^3/(a/b)^(2/3)*ln(x^(1/3)+(a/b)^(1/3))-1/2*a^2/b^3/(a/b)^(2/3)*ln(x^(2/3)-(
a/b)^(1/3)*x^(1/3)+(a/b)^(2/3))+a^2/b^3/(a/b)^(2/3)*3^(1/2)*arctan(1/3*3^(1/2)*(2/(a/b)^(1/3)*x^(1/3)-1))

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maxima [A]  time = 3.05, size = 128, normalized size = 1.04 \[ \frac {\sqrt {3} a^{2} \arctan \left (\frac {\sqrt {3} {\left (2 \, x^{\frac {1}{3}} - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{b^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} - \frac {a^{2} \log \left (x^{\frac {2}{3}} - x^{\frac {1}{3}} \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{2 \, b^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} + \frac {a^{2} \log \left (x^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{b^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} + \frac {3 \, {\left (b x^{\frac {4}{3}} - 4 \, a x^{\frac {1}{3}}\right )}}{4 \, b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)/(b*x+a),x, algorithm="maxima")

[Out]

sqrt(3)*a^2*arctan(1/3*sqrt(3)*(2*x^(1/3) - (a/b)^(1/3))/(a/b)^(1/3))/(b^3*(a/b)^(2/3)) - 1/2*a^2*log(x^(2/3)
- x^(1/3)*(a/b)^(1/3) + (a/b)^(2/3))/(b^3*(a/b)^(2/3)) + a^2*log(x^(1/3) + (a/b)^(1/3))/(b^3*(a/b)^(2/3)) + 3/
4*(b*x^(4/3) - 4*a*x^(1/3))/b^2

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mupad [B]  time = 0.07, size = 126, normalized size = 1.02 \[ \frac {3\,x^{4/3}}{4\,b}-\frac {3\,a\,x^{1/3}}{b^2}+\frac {a^{4/3}\,\ln \left (\frac {9\,a^{7/3}}{b^{1/3}}+9\,a^2\,x^{1/3}\right )}{b^{7/3}}+\frac {a^{4/3}\,\ln \left (9\,a^2\,x^{1/3}+\frac {9\,a^{7/3}\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{b^{1/3}}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{b^{7/3}}-\frac {a^{4/3}\,\ln \left (9\,a^2\,x^{1/3}-\frac {9\,a^{7/3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{b^{1/3}}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}{b^{7/3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(4/3)/(a + b*x),x)

[Out]

(3*x^(4/3))/(4*b) - (3*a*x^(1/3))/b^2 + (a^(4/3)*log((9*a^(7/3))/b^(1/3) + 9*a^2*x^(1/3)))/b^(7/3) + (a^(4/3)*
log(9*a^2*x^(1/3) + (9*a^(7/3)*((3^(1/2)*1i)/2 - 1/2))/b^(1/3))*((3^(1/2)*1i)/2 - 1/2))/b^(7/3) - (a^(4/3)*log
(9*a^2*x^(1/3) - (9*a^(7/3)*((3^(1/2)*1i)/2 + 1/2))/b^(1/3))*((3^(1/2)*1i)/2 + 1/2))/b^(7/3)

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sympy [A]  time = 25.86, size = 240, normalized size = 1.95 \[ \begin {cases} \tilde {\infty } x^{\frac {4}{3}} & \text {for}\: a = 0 \wedge b = 0 \\\frac {3 x^{\frac {7}{3}}}{7 a} & \text {for}\: b = 0 \\\frac {3 x^{\frac {4}{3}}}{4 b} & \text {for}\: a = 0 \\- \frac {\sqrt [3]{-1} a^{\frac {4}{3}} \sqrt [3]{\frac {1}{b}} \log {\left (- \sqrt [3]{-1} \sqrt [3]{a} \sqrt [3]{\frac {1}{b}} + \sqrt [3]{x} \right )}}{b^{2}} + \frac {\sqrt [3]{-1} a^{\frac {4}{3}} \sqrt [3]{\frac {1}{b}} \log {\left (4 \left (-1\right )^{\frac {2}{3}} a^{\frac {2}{3}} \left (\frac {1}{b}\right )^{\frac {2}{3}} + 4 \sqrt [3]{-1} \sqrt [3]{a} \sqrt [3]{x} \sqrt [3]{\frac {1}{b}} + 4 x^{\frac {2}{3}} \right )}}{2 b^{2}} + \frac {\sqrt [3]{-1} \sqrt {3} a^{\frac {4}{3}} \sqrt [3]{\frac {1}{b}} \operatorname {atan}{\left (\frac {\sqrt {3}}{3} - \frac {2 \left (-1\right )^{\frac {2}{3}} \sqrt {3} \sqrt [3]{x}}{3 \sqrt [3]{a} \sqrt [3]{\frac {1}{b}}} \right )}}{b^{2}} - \frac {3 a \sqrt [3]{x}}{b^{2}} + \frac {3 x^{\frac {4}{3}}}{4 b} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(4/3)/(b*x+a),x)

[Out]

Piecewise((zoo*x**(4/3), Eq(a, 0) & Eq(b, 0)), (3*x**(7/3)/(7*a), Eq(b, 0)), (3*x**(4/3)/(4*b), Eq(a, 0)), (-(
-1)**(1/3)*a**(4/3)*(1/b)**(1/3)*log(-(-1)**(1/3)*a**(1/3)*(1/b)**(1/3) + x**(1/3))/b**2 + (-1)**(1/3)*a**(4/3
)*(1/b)**(1/3)*log(4*(-1)**(2/3)*a**(2/3)*(1/b)**(2/3) + 4*(-1)**(1/3)*a**(1/3)*x**(1/3)*(1/b)**(1/3) + 4*x**(
2/3))/(2*b**2) + (-1)**(1/3)*sqrt(3)*a**(4/3)*(1/b)**(1/3)*atan(sqrt(3)/3 - 2*(-1)**(2/3)*sqrt(3)*x**(1/3)/(3*
a**(1/3)*(1/b)**(1/3)))/b**2 - 3*a*x**(1/3)/b**2 + 3*x**(4/3)/(4*b), True))

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